16x^2-48x+56=20

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Solution for 16x^2-48x+56=20 equation: 



16x^2-48x+56=20

We move all terms to the left:

16x^2-48x+56-(20)=0

We add all the numbers together, and all the variables

16x^2-48x+36=0

a = 16; b = -48; c = +36;
Δ = b2-4ac
Δ = -482-4·16·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{48}{32}=1+1/2$

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